6x^2-6x-75=0

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Solution for 6x^2-6x-75=0 equation:



6x^2-6x-75=0
a = 6; b = -6; c = -75;
Δ = b2-4ac
Δ = -62-4·6·(-75)
Δ = 1836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1836}=\sqrt{36*51}=\sqrt{36}*\sqrt{51}=6\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{51}}{2*6}=\frac{6-6\sqrt{51}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{51}}{2*6}=\frac{6+6\sqrt{51}}{12} $

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